What is the vertex form of #y=x^2 +x-6#? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer iceman Feb 23, 2016 #y=(x+1/2)^2-25/4# Explanation: #y=x^2+x-6# => complete the square: #y=x^2+x+(1/2)^2-6-1/4# => simplify: #y=(x+1/2)^2-25/4# => in the vertex form Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 4560 views around the world You can reuse this answer Creative Commons License