What is the vertex form of y=x2−x−72?
1 Answer
Jul 24, 2016
y=(x−12)2−7214
Explanation:
Given
y=x2−x−72
Find the Vertex
X-cordinate of the vertex
x=−b2a=−(−1)2×1=12
Atx=12;y=(12)2−12−72=14−12−72=−7214
Vertex for of the quardratic equation is
y=a(x−h)+k
Where
h=12
k=−7214
a=1
Substitute these values in the formula
y=(x−12)2−7214