What is the vertex form of $y = (x - 4) (2 x + 2) - x^{2} + 2 x$ $y= (x-4)(2x+2)-x^2+2x$ ?

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What is the vertex form of $y = (x - 4) (2 x + 2) - x^{2} + 2 x$ $y= (x-4)(2x+2)-x^2+2x$ ?

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Answer 1 · 2016-01-06T13:15:55

$y = {(x - \frac{7}{2})}^{2} - \frac{111}{4}$ $y = (x-7/2)^2 -111/4$

Explanation:

First simplify by multiplying out and grouping like terms together to get standard form.
$y = (2 x^{2} - 8 x + 2 x - 8) - x^{2} + 2 x$ $y =(2x^2 -8x +2x -8) -x^2 +2x$
$y = x^{2} - 7 x - 8$ $y = x^2 -7x -8$
Then the vertex form is
$y = {(x - \frac{7}{2})}^{2} - \frac{79}{4} - 8$ $y = (x-7/2)^2 -79/4 -8$
$y = {(x - \frac{7}{2})}^{2} - \frac{111}{4}$ $y = (x-7/2)^2 -111/4$

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What is the vertex form of $y = (x - 4) (2 x + 2) - x^{2} + 2 x$ $y= (x-4)(2x+2)-x^2+2x$ ?

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What is the vertex form of y=(x−4)(2x+2)−x2+2x y= (x-4)(2x+2)-x^2+2x?

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What is the vertex form of $y = (x - 4) (2 x + 2) - x^{2} + 2 x$ $y= (x-4)(2x+2)-x^2+2x$ ?