What is the vertex form of $y=(x – 8)(x + 5)$ ?

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Answer 1 · 2017-07-10T14:46:05

Vertex form is $y = (x - 3/2)^2 - 169/4$

Start by multiplying out.

$y = x^2 - 3x - 40$

Now complete the square.

$y = 1(x^2 - 3x + 9/4 - 9/4) - 40$

$y = 1(x^2 - 3x + 9/4) - 9/4 - 40$

$y = 1(x - 3/2)^2 - 169/4$

Hopefully this helps!

What is the vertex form of y=(x – 8)(x + 5) y=(x – 8)(x + 5) ?