What is the vertex form of #y= x(x - 7) #? Algebra Quadratic Equations and Functions Vertex Form of a Quadratic Equation 1 Answer Alan P. Mar 14, 2016 #y=1(x-7/2)^2+(-49/4)# Explanation: The general vertex form is #color(white)("XXX")y=color(green)(m)(x-color(red)(a))^2+color(blue)(b)# with vertex at #(color(red)(a),color(blue)(b))# Given #color(white)("XXX")y=x(x-7)# #color(white)("XXX")y=x^2-7x# #color(white)("XXX")y=x^2-7x+(7/2)^2 - (7/2)^2# #color(white)("XXX")y=(x-7/2)^2-49/4# #color(white)("XXX")y=color(green)(1)(x-color(red)(7/2))^2+(color(blue)(-49/4))# Answer link Related questions What is the Vertex Form of a Quadratic Equation? How do you find the vertex form of a quadratic equation? How do you graph quadratic equations written in vertex form? How do you write #y+1=-2x^2-x# in the vertex form? How do you write the quadratic equation given #a=-2# and the vertex #(-5, 0)#? What is the quadratic equation containing (5, 2) and vertex (1, –2)? How do you find the vertex, x-intercept, y-intercept, and graph the equation #y=-4x^2+20x-24#? How do you write #y=9x^2+3x-10# in vertex form? What is the vertex of #y=-1/2(x-4)^2-7#? What is the vertex form of #y=x^2-6x+6#? See all questions in Vertex Form of a Quadratic Equation Impact of this question 1124 views around the world You can reuse this answer Creative Commons License