What is the vertex of the graph of $y = (x – 3)^2 + 4$ ?

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Answer 1 · 2017-06-09T13:49:40

Vertex is $(3,4)$

In a vertex form of equation such as

$(y-k)=a(x-h)^2$

the vertex is $(h,k)$

As $y=(x-3)^2+4$

$hArr(y-4)=1xx(x-3)^2$

the vertex is $(3,4)$
graph{(x-3)^2+4 [-7.585, 12.415, -0.96, 9.04]}

What is the vertex of the graph of y = (x – 3)^2 + 4y = (x – 3)^2 + 4?