Question

What is the vertex of the parabola `y = -4(x + 3)^2 - 6`?

Answer 1

vertex = (- 3 , -6 )

Explanation:

The vertex form of the quadratic is `y = a(x - h )^2 + k`

where (h , k ) are the coordinates of the vertex.

the equation here: `y = -4(x + 3 )^2 - 6 " is in this form "`

and by comparison: h = - 3 , k = - 6

hence vertex is ( -3 , -6 )