Question

What is the vertex of the parabola `y=x^2 -4`?

Answer 1

`(0,-4)`

Explanation:

To find the vertex, we first need to find the axis of symmetry, which is

`x = -b/(2a)`

In this case, we have `b=0` and `a=1`, so

`x = -0/(2(1)) = 0`

Our axis of symmetry is `0`. This is the `x` value of the vertex. Now, to find the `y` value, we need to plug this value of `x` back into the equation.

`y = x^2-4`

`y = 0^2-4`

`y = -4`

So the `y` coordinate of the vertex is `-4`.

This means our vertex is `(0,-4)`.

Final Answer