What is the vertex of the parabola y=(x-8)^2+7?

1 Answer
Mar 1, 2016

(8,7)

Explanation:

The standard form of a parabola in vertex form is.

y =a (x-h)^2 + k " where (h,k) are the coords of vertex "

the equation : y = (x-8)^2 + 7 " is in this form "

and by comparison vertex (h,k) = (8,7)

here is the graph of the parabola,showing the vertex.
graph{(x-8)^2+7 [-22.2, 22.18, -11.1, 11.1]}