What is the vertex of this parabola $x = {(y - 2)}^{2} + 4$ $x = (y - 2)^2 + 4$ ?

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Answer 1 · 2015-05-10T13:22:09

$(4, 2)$ $(4, 2)$ i.e. $x = 4$ $x = 4$ , $y = 2$ $y = 2$ .

The axis of this parabola is parallel to the x-axis, with a minimum $x$ $x$ value when $(y - 2) = 0$ $(y - 2) = 0$ , i.e. $y = 2$ $y = 2$ .

What is the vertex of this parabola x = (y - 2)^2 + 4x=(y−2)2+4x = (y - 2)^2 + 4?