Question

What is the vertex of `y= -1/16(2x-4)^2+8`?

Answer 1

`(2,8)`

Explanation:

This is almost in vertex form, except for that there is a `2` being multiplied by the `x`.

`y=a(x-h)^2+k`

`y=-1/16(2x-4)(2x-4)+8`

`y=-1/4(x-2)^2+8`

(Since the `2x-4` term is squared, a `2` is factored from each term.)

This is now in vertex form.

The center is at `(h,k)rarr(2,8)`.

graph{-1/16(2x-4)^2+8 [-13.78, 14.7, -2.26, 11.98]}