What is the vertex of $y = - 3 {(x - 2)}^{2} - 1$ $y= -3(x-2)^2-1$ ?

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Answer 1 · 2018-04-09T21:43:10

$(2, - 1)$ $(2, -1)$

This equation is in vertex form

$y = a {(x - h)}^{2} + k \to$ $y=a(x-h)^2+k rarr$ $h, k$ $h, k$ represents the vertex

In this equation, $- 3$ $-3$ represents $a$ $a$ , $2$ $2$ represents $h$ $h$ , and $- 1$ $-1$ represents $k$ $k$ .

$h, k$ $h, k$ in this case is $2, - 1$ $2, -1$

What is the vertex of y=−3(x−2)2−1y= -3(x-2)^2-1?