What is the vertex of $y=4(9x+2)^2+1$ ?

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Answer 1 · 2015-11-25T23:50:11

Find vertex of y = 4(9x + 2)^2 + 1
Ans: Vertex $(-2/9, 1)$

$y = 4(81)(x + 2/9)^2 + 1$
$y = 324(x + 2/9)^2 + 1$
This is the vertex form of y. Therefor, the vertex is
Vertex $(-2/9, 1)$

What is the vertex of y=4(9x+2)^2+1y=4(9x+2)^2+1?