Question

What is the vertex of `y=9(5x-2)^2+3`?

Answer 1

The vertex form is written as `y = a(x - h)^2 + k`, where the a value determines the direction of opening (if a > 0, then it opens upwards and if a < 0, then it opens downward); h represents the x-coordinate of the vertex; k represents the y-coordinate of the vertex; x and y represent the x- and y-coordinates of a point on the parabola, other than the vertex.

Hence in our case we write this as

`y=9*(5(x-2/5))^2+3=>y=9*5^2*(x-2/5)^2+3`