What is the vertex of $y=x^2-4x+3$ ?

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Answer 1 · 2016-01-04T00:45:53

The x-coordinate can be found using a simple formula ...

The general form of a quadratic is $y=ax^2+bx+c$

For this problem, $a=1, b=-4, c=3$

$x=(-b)/(2a)=-(-4)/(2xx1)=2$

Now that we now the x-coordinate of the vertex is $2$ , insert it into the equation to find y ...

$y(2)=2^2-4(2)+3=-1$

Vertex $=(2,-1)$

hope that helped

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What is the vertex of y=x^2-4x+3 y=x^2-4x+3 ?