What is $y = x^{2} + 10 x + 23$ $y=x^2 + 10x + 23$ in vertex form?

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Answer 1 · 2016-11-15T23:52:06

$y = {(x - - 5)}^{2} - 2$ $y = (x - -5)^2 - 2$

Add $h^{2} - h^{2}$ $h^2 - h^2$ to the equation:

$y = x^{2} + 10 x + h^{2} - h^{2} + 23$ $y = x^2 + 10x + h^2 - h^2 + 23$

$h = - \frac{b}{2 a} = - \frac{10}{2} = - 5$ $h = -b/(2a) = -10/2 = -5$

$y = {(x - - 5)}^{2} - 25 + 23$ $y = (x - -5)^2 - 25 + 23$

$y = {(x - - 5)}^{2} - 2$ $y = (x - -5)^2 - 2$

What is y=x2+10x+23y=x^2 + 10x + 23 in vertex form?