What is y = x^2-16x+40 written in vertex form?
1 Answer
Oct 9, 2015
#y=(x-8)^2-24#
Explanation:
#y=x^2-16x+40#
Find the fertex-
#x=(-b)/(2a)=(-(-16))/(2 xx 1)=16/2=8#
At
#y=8^2-16(8)+40#
#y=64-128+40#
#y=104-128=-24#
#y=-24#
Vertex form of the equation is-
#y=a(x-h)^2+k#
Hear#h, k# are the vertex
#x=h#
#y=k#
#y=1(x-(8))^2+(-24)#
#y=(x-8)^2-24#