What's the derivative of arctan(8^x)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer A. S. Adikesavan Apr 15, 2016 (8^x ln 8)/(1+8^(2x)) Explanation: Let u = 8^x=e^(x ln 8) and y = arc tan 8^x. d/dx(y)=d/du(y)d/dx(u). =1/(1+u^2)(ln 8 e^(x ln 8)) = (8^x ln 8)/(1+8^(2x)) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1914 views around the world You can reuse this answer Creative Commons License