What's the derivative of $arctan(x^2+1)$ ?

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Answer 1 · 2016-11-22T00:35:29

$d/dx$ arctan( $x^2 +1$ ) = $(1/(1+(x^2+1)^2))*2x$

Consider the derivative of arctan(u)

$d/dx arctan(u) = (1/(1+u^2)) * d/dx (u)$

In your question: u = $(x^2+1)$

What's the derivative of arctan(x^2+1)arctan(x^2+1)?