What symmetry does the polar curve $r^2 = 4sin(2t)$ ?

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Answer 1 · 2016-01-31T04:38:03

The polar curve $r^2=4 sin (2t)$ is symmetric with the line $y=x$ that cuts the first and third quadrants into two equal parts.

The graph of $r^2=4 sin (2t)$ is the one containing loops, and $y=x$ the diagonal line.

graph{((x^2+y^2)^2-8xy)(y-x)=0[-6,6,-3,3]}

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What symmetry does the polar curve r^2 = 4sin(2t)r^2 = 4sin(2t)?