Whats the derivative of sin^-1 * (5x)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Konstantinos Michailidis Sep 27, 2015 See explanation Explanation: Set arcsinx=cos^(-1)x hence we know that d((arcsinx))/dx=1/(sqrt(1-x^2) hence for a function u(x) d(arcsinu(x))/dx=1/sqrt(1-u^2(x))*du/dx hence for u=5x we get d(arcsin5x)/dx=5/(sqrt(1-25x^2)) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 17314 views around the world You can reuse this answer Creative Commons License