Where is the vertex for #y= |x/3-4 |#?

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Answer 1 · 2014-10-26T00:25:26

By pulling #1/3# out of the absolute value sign, we have

#y=1/3|x-12|#.

Remember that #y=|x|# has a vertex at #(0,0)#.

Since vertical shrinkage does not affect the vertex, #y=1/3|x|# still has a vertex at #(0,0)#.

By shifting right by 12 units, #y=1/3|x-12|# has a vertex at #(12,0)#.

Hence, the vertex is at #(12,0)#.

I hope that this was helpful.