Why does tan(x+(pi/2))=cot(x)? or cos((pi/2)-x)=sin(x) and is it like that with (3pi)/2 as well?

Please explain what's so special with pi/2 and (3pi)/2

1 Answer
Jun 3, 2018

a. tan (x + pi/2) = sin (x + pi/2)/(cos (x + pi/2))
Reminder of trig identities:
sin (x + pi/2) = cos x
cos (x + pi/2) = - sin x
Therefor,
tan (x + pi/2) = (cos x)/(-sin x) = - cot x
To fully understand the property of complementary arcs, we prove theses below trig identities:
cos (pi/2 + x) = cos (pi/2).cos x - sin (pi/2).sin x = - sin x
sin (pi/2 + x) = sin x.cos (pi/2) + cos x.sin (pi/2) = cos x
cos (pi/2 - x) = cos (pi/2.cos x + sin (pi/2).sin x = sin x
sin (pi/2 - x) = sin (pi/2).cos x + sin x.cos (pi/2) = cos x