Why is cos(4pi/3) = - cos(pi/3)? Trigonometry Right Triangles Relating Trigonometric Functions 1 Answer Shwetank Mauria May 2, 2016 Please see below. Explanation: cos(4pi/3)=cos(pi+pi/3) Now using cos(A+B)=cosAcosB-sinAsinB, the above is equal to cospicos(pi/3)-sinpisin(pi/3) = (-1)xxcos(pi/3)-0xxsin(pi/3) = -cos(pi/3) Answer link Related questions What does it mean to find the sign of a trigonometric function and how do you find it? What are the reciprocal identities of trigonometric functions? What are the quotient identities for a trigonometric functions? What are the cofunction identities and reflection properties for trigonometric functions? What is the pythagorean identity? If sec theta = 4, how do you use the reciprocal identity to find cos theta? How do you find the domain and range of sine, cosine, and tangent? What quadrant does cot 325^@ lie in and what is the sign? How do you use use quotient identities to explain why the tangent and cotangent function have... How do you show that 1+tan^2 theta = sec ^2 theta? See all questions in Relating Trigonometric Functions Impact of this question 3283 views around the world You can reuse this answer Creative Commons License