Write an equation for a line that is parallel to the equation y= -9. The line must pass through the points (4, -11). How do I do this?

↳Redirected from "Suppose that I don't have a formula for #g(x)# but I know that #g(1) = 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Gió
Sep 11, 2015

I should get #y=-11#

Explanation:

In this cas you are lucky...your original line is perfectly horizontal (slope #=0#)!!!
So, to be parallel you need another horizontal line that passes through #-11# i.e.:
#y=-11#

In general you can write the equation of a line as:
#y=mx+c#
where:
#m=# slope
#c=# y-intercept
so here you need:
slope #=m=0#
y-intercept #=c=-11#

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