Write the polynomial in factored form? x3+2x215x

Select one:
a. 3x(x+5)(x+1)
b. x(x3)(x+5)
c. 5x(x+1)(x3)
d. x(x+5)(x+3)

1 Answer
Mar 3, 2017

b. x(x3)(x+5)

Explanation:

Note that the coefficient of x3 is 1, so we can eliminate a and c immediately.

Looking at the coefficient of x, which is negative, we can also rule out d, which is all positive.

So the only possibility is b.

Does it work?

x(x3)(x+5)=x(x2+(53)x+(3)(5))

x(x3)(x+5)=x(x2+2x15)

x(x3)(x+5)=x3+2x215x


Footnote

If we were factoring this without the multiple choice answers, then we could proceed as follows:

Given:

x3+2x215x

First note that all of the terms are divisible by x, so we can separate that out as a factor:

x3+2x215x=x(x2+2x15)

Next look for a pair of factors of 15 which differ by 2.

The pair 5,3 works, so we find:

x2+2x15=(x+5)(x3)

Putting it all together we have:

x3+2x215x=x(x+5)(x3)