Question

You have 2.0 x 10²² moles of HCl in the equation below. How many moles of CaCl₂ will you make?

Answer 1

Well, clearly you will make `1.0xx10^22*mol` of `CaCl_2`...

Explanation:

And we interrogate the stoichiometric equation....

`Ca(s) + 2HCl(aq) rarr CaCl_2(aq) + H_2(g)uarr`

And given two equiv of hydrogen chloride we make one equiv of calcium chloride....

...a mass of ..........

`1.0xx10^22*molxx110.98*g*mol^-1xx10^-3*kg*g^-1=1.11xx10^21*kg`

...and this is not an insignificant mass of stuff...