How do you graph y = -abs(x+10)?

1 Answer
Apr 2, 2015

First, lets remember the absolute value operator:

AAc in RR (for every element c in the real numbers set)

if c>=0, abs(c) = c

if c<0, abs(c) = -c

When graphing an absolute value operator, there are actually 2 graphs. Because the absolute value operation behaves in 2 different ways related to its input.

So we need to find the critical point of the absolute value. This means, we need to find the exact value of x where the greater values will result the output as is and the smaller values will result the output as negated.

Now it is obvious that 0 is the critical point of the absolute value operation.

To find the critical point in this problem:

x+10=0

x=-10

When x is greater than -10 the input will be positive. When smaller, it will be negative.

Now we are ready to graph the line.

When x>=-10, y = - (x+10) = -x - 10

When x<-10, y = - (-1) * (x+10) = x + 10

The graph will look like this:

graph{y = - abs(x+10) [-20, 10, -5, 5]}

Why there is no positive y? Remember the conditions while graphing the lines. (x>=10 and x<-10) When you try to plug some values of x you will see that there is no chance for y to be positive.