Question

How to find the x and y-intercept given `y= 4x-2`?

Answer 1

`I_x ={x`-intercept`}={(1/2,0)}`
`I_y ={y`-intercept`}={(0,-2)}`

The intercepts are made combining the equation of the two functions together

So, you know the equation of the `x` axis is `y=0`, and the equation of the `y` axis is `x=0`)
`I_x={y=4x-2` `&` `y=0},I_y={y=4x-2` `&` `x=0}`
so

`I_x={(x,0) : 4x-2=0}={(1/2,0)}`
`I_y={(0,y):y=4*0-2}={(0,-2)}`

graph{4x-2 [-10, 10, -5, 5]}