How to find the x and y-intercept given y= 4x-2y=4x−2?

1 Answer
Alberto M.
May 9, 2015

I_x ={xIx={x-intercept}={(1/2,0)}}={(12,0)}
I_y ={yIy={y-intercept}={(0,-2)}}={(0,−2)}

The intercepts are made combining the equation of the two functions together

So, you know the equation of the xx axis is y=0y=0, and the equation of the yy axis is x=0x=0)
I_x={y=4x-2Ix={y=4x−2 && y=0},I_y={y=4x-2y=0},Iy={y=4x−2 && x=0}x=0}
so

I_x={(x,0) : 4x-2=0}={(1/2,0)}Ix={(x,0):4x−2=0}={(12,0)}
I_y={(0,y):y=4*0-2}={(0,-2)}Iy={(0,y):y=4⋅0−2}={(0,−2)}

graph{4x-2 [-10, 10, -5, 5]}

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