How do you solve the system using the elimination method for -3x+2y=-6 and 2x+2y=5?

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Answer 1 · 2015-07-02T13:23:30

The solution is:
$color(blue)(x=11/5$
$color(blue)( y=3/10$

$-3x+color(blue)(2y)=-6$ .......equation $(1)$

$2x+color(blue)(2y)=5$ ............equation $(2)$

Subtracting equation $(2)$ from $(1)$ to eliminate $color(blue)(2y$

$-3x+cancelcolor(blue)(2y)=-6$
$-2x-cancelcolor(blue)(2y)=-5$

$-5x = -11$
$color(blue)(x=11/5$

Finding $y$ from equation $1$

$-3x+2y=-6$

$2y=-6 +3x$

$y=(-6 +3x )/2$

$y=(-6 +3 * (11/5) )/2$

$y=(-30 +33 )/(5 * 2$

$color(blue)( y=3/10$