How do you simplify #sqrt 80 / sqrt 5#?

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Answer 1 · 2015-09-17T13:36:04

It is #sqrt80/sqrt5=(sqrt((5*16)/5))=sqrt(16)=4#

Answer 2 · 2015-09-17T13:39:01

#4#

#sqrt80/sqrt5# can also be written as #sqrt((80/5)# or #(80/5)^(1/2)#

Simplify #80/5# or in other terms, divide #80# by #5#;

#=sqrt((cancel(80)16)/(cancel(5)1))#

#=sqrt16#

#=4#