How do you solve #10 1/2 = x + 1 1/2 #?
1 Answer
Explanation:
Isolate
#10 1/2-1 1/2=x + cancel(1 1/2)- cancel(1 1/2)#
This is equivalent to
#(10 * 2 + 1)/2 - (1 * 2 + 1)/2 = x#
#21/2 - 3/2 = x implies x = 18/2 = 9#
Isolate
#10 1/2-1 1/2=x + cancel(1 1/2)- cancel(1 1/2)#
This is equivalent to
#(10 * 2 + 1)/2 - (1 * 2 + 1)/2 = x#
#21/2 - 3/2 = x implies x = 18/2 = 9#