How do you simplify (4sqrt7-8sqrt3)(5sqrt7+10sqrt3)?

1 Answer
May 4, 2016

-100

Explanation:

Expand the brackets using FOIL or multiply each term in the 2nd bracket by each term in the 1st.

4sqrt7(5sqrt7+10sqrt3)-8sqrt3(5sqrt7+10sqrt3)

Noting that : sqrtaxxsqrta=a

and from the question here sqrt7xxsqrt7=7

distribute 1st bracket

rArr(4sqrt7xx5sqrt7)+(4sqrt7xx10sqrt3)=140+40sqrt21

[" using " sqrtaxxsqrtbhArrsqrtab]"so"sqrt7xxsqrt3=sqrt21

distribute 2nd bracket

rArr(-8sqrt3xx5sqrt7)+(-8sqrt3xx10sqrt3)

=-40sqrt21-240

Combining the 2 expansions

140+40sqrt21-40sqrt21-240

[Note : 40sqrt21-40sqrt21=0]

rArr(4sqrt7-8sqrt3)(5sqrt7+10sqrt3)=140-240=-100