How do you solve #sqrt(4p+1)=2p-1#?

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Answer 1 · 2016-05-07T02:52:58

#p=0 or p=2#

First, square both sides of the equation.

#(sqrt(4p+1))^2 = (2p-1)^2#

#4p+1 = 4p^2-4p+1#

Move all terms to the same side so that one side of the equation is #0#.

#0=4p^2-4p-4p+1-1#

Combine like terms.

#0=4p^2-8p#

Factorise a #4p#
#0=4p(p-2)#

#4p=0 or p-2 = 0#

#p= 0 or p=2#