Question

How do you solve for x in `sqrt(42-x)+x =13`?

Answer 1

Okay start by

Rewriting equation as `sqrt(42- x ) = 13 - x`

Now square both sides

So we are left with the equation `42 - x = (13 - x)^2 = x^2− 26x +169`

Next step bring all the terms to one side of the equation
SO `x^2 - 26 x + 169- 42 + x = 0`

So using the quadratic formula i get that The values of x are = `x=17.908326913195985,7.091673086804016`