Question

How do you solve `6=sqrt(b+13)`?

Answer 1

`b=23`

Explanation:

As `6=sqrt(b+13)`

squaring we get

`36=b+13`

or `36-13=b+13-13`

or `23=b`

Answer 2

`b=23`

Explanation:

`color(blue)"square both sides"`

`6^2=(sqrt(b+13))^2`

`36=b+13`

`"subtract 13 from both sides"`

`23=brArrb=23`

`color(blue)"As a check"`

`sqrt(23+13)=sqrt36=6larr" correct"`