How do you solve $6 = \sqrt{b + 13}$ $6=sqrt(b+13)$ ?

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How do you solve $6 = \sqrt{b + 13}$ $6=sqrt(b+13)$ ?

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Answer 1 · 2018-07-02T09:36:23

$b = 23$ $b=23$

Explanation:

As $6 = \sqrt{b + 13}$ $6=sqrt(b+13)$

squaring we get

$36 = b + 13$ $36=b+13$

or $36 - 13 = b + 13 - 13$ $36-13=b+13-13$

or $23 = b$ $23=b$

Answer 2 · 2018-07-02T09:37:05

$b = 23$ $b=23$

Explanation:

$square both sides$ $color(blue)"square both sides"$

$6^{2} = {(\sqrt{b + 13})}^{2}$ $6^2=(sqrt(b+13))^2$

$36 = b + 13$ $36=b+13$

$subtract 13 from both sides$ $"subtract 13 from both sides"$

$23 = b \Rightarrow b = 23$ $23=brArrb=23$

$As a check$ $color(blue)"As a check"$

$\sqrt{23 + 13} = \sqrt{36} = 6 \leftarrow correct$ $sqrt(23+13)=sqrt36=6larr" correct"$

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How do you solve $6 = \sqrt{b + 13}$ $6=sqrt(b+13)$ ?

2 Answers

Explanation:

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