How do you solve $\sqrt{x + 15} = \sqrt{3 x - 3}$ $\sqrt{x+15}=\sqrt{3x-3}$ ?

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How do you solve $\sqrt{x + 15} = \sqrt{3 x - 3}$ $\sqrt{x+15}=\sqrt{3x-3}$ ?

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Answer 1 · 2018-03-01T21:32:59

$x = 9$ $x=9$

Explanation:

$To 'undo' the radicals square both sides$ $"To 'undo' the radicals square both sides"$

${(\sqrt{x + 15})}^{2} = {(\sqrt{3 x - 3})}^{2}$ $(sqrt(x+15))^2=(sqrt(3x-3))^2$

$\Rightarrow x + 15 = 3 x - 3$ $rArrx+15=3x-3$

$subtract (x + 15) from both sides$ $"subtract "(x+15)" from both sides"$

$\Rightarrow 0 = 2 x - 18$ $rArr0=2x-18$

$\Rightarrow 2 x = 18 \Rightarrow x = 9$ $rArr2x=18rArrx=9$

$As a check$ $color(blue)"As a check"$

$substitute x = 9 into the equation and if both sides are$ $"substitute "x=9" into the equation and if both sides are"$
$equal then it is the solution$ $"equal then it is the solution"$

$left side = \sqrt{24} = 2 \sqrt{6}$ $"left side "=sqrt24=2sqrt6$

$right side = \sqrt{24} = 2 \sqrt{6}$ $"right side "=sqrt24=2sqrt6$

$\Rightarrow x = 9 is the solution$ $rArrx=9" is the solution"$

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How do you solve $\sqrt{x + 15} = \sqrt{3 x - 3}$ $\sqrt{x+15}=\sqrt{3x-3}$ ?

1 Answer

Explanation:

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How do you solve \sqrt{x+15}=\sqrt{3x-3}√x+15=√3x−3\sqrt{x+15}=\sqrt{3x-3}?

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How do you solve $\sqrt{x + 15} = \sqrt{3 x - 3}$ $\sqrt{x+15}=\sqrt{3x-3}$ ?