How do you solve $sqrt(x-5) = 2sqrt6$ ?

Question

1904 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-25T21:59:42

$x=29$

Square both sides.

$(sqrt(x-5))^2=(2sqrt6)^2$

On the left side, the square root and the exponent of $2$ undo one another, leaving just $x-5$ .

On the right side, to square $2sqrt6$ , we see that $(2sqrt6)^2=2^2*(sqrt6)^2=4*6=24$ .

$x-5=24$

$x=29$

Answer 2 · 2016-05-25T21:59:57

$x = 29$

square both sides
$x - 5 = (2sqrt6)^2 -> x - 5 = 2^2 xx 6 -> x - 5 = 24$
add 5 to both sides
$x = 29$

How do you solve sqrt(x-5) = 2sqrt6sqrt(x-5) = 2sqrt6?