How do you solve 2/3 = 2 - (5x-3)/(x-1)? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Burglar Jun 19, 2016 x=5/11. Explanation: 2/3=2-(5x-3)/(x-1) 2/3-2=-(5x-3)/(x-1) -4/3=-(5x-3)/(x-1) 4/3=(5x-3)/(x-1) 4/3(x-1)=5x-3 4(x-1)=3(5x-3) 4x-4=15x-9 4x-15x=-9+4 -11x=-5 x=5/11. Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve 5x-\frac{1}{x}=4? How do you solve -3 + \frac{1}{x+1}=\frac{2}{x} by finding the least common multiple? What is the least common multiple for \frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6} and how do... How do you solve \frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}? How do you solve by clearing the denominator of 3/x+2/x^2=4? How do you solve 2/(x^2+2x+1)-3/(x+1)=4? How do you solve equations with rational expressions 1/x+2/x=10? How do you solve for y in (y+5)/ 2 - y/3 =1? See all questions in Clearing Denominators in Rational Equations Impact of this question 1501 views around the world You can reuse this answer Creative Commons License