How do you simplify $\frac{\sqrt{2}}{2 \sqrt{3}}$ $sqrt2/(2sqrt3)$ ?

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How do you simplify $\frac{\sqrt{2}}{2 \sqrt{3}}$ $sqrt2/(2sqrt3)$ ?

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Answer 1 · 2016-08-13T21:55:30

$\frac{1}{\sqrt{6}}$ $1/(sqrt(6))$

Explanation:

Can write $2 = \sqrt{2} \sqrt{2}$ $2 = sqrt(2)sqrt(2)$

$\frac{\sqrt{2}}{\sqrt{2} \sqrt{2} \sqrt{3}} = \frac{1}{\sqrt{2} \sqrt{3}} = \frac{1}{\sqrt{6}}$ $(sqrt(2))/(sqrt(2)sqrt(2)sqrt(3)) = 1/(sqrt(2)sqrt(3)) = 1/(sqrt(6))$

Answer 2 · 2016-08-13T22:43:35

$\frac{\sqrt{6}}{6}$ $sqrt6/6$

Explanation:

It is generally not good practice to leave a radical in the denominator so we try to change the denominator into a rational number.

This is called rationalising the denominator.

$\frac{\sqrt{2}}{2 \sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} \frac{\sqrt{3}}{\sqrt{3}} = 1$ $sqrt2/(2sqrt3) xxsqrt3/sqrt3 " "sqrt3/sqrt3 = 1$

= $\frac{\sqrt{6}}{2 \times 3}$ $sqrt6/(2 xx 3)$

$\frac{\sqrt{6}}{6}$ $sqrt6/6$

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How do you simplify $\frac{\sqrt{2}}{2 \sqrt{3}}$ $sqrt2/(2sqrt3)$ ?

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