How do you differentiate #f(x)=tanx+cotx#?

1 Answer
Emmy
Sep 26, 2016

#dy/dx = sec^(2)x+(-csc^(2)x)#

Explanation:

The derivative is distributive over addition and subtraction.

Hence:

#dy/dx = D_x[tanx] + D_x[cotx]#

Differentiating we get:

#dy/dx = sec^(2)x+(-csc^(2)x)#

It is important to know the derivatives of the trigonometric functions.

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