How do you multiply $(x + 3) (x - 2) (6 x - 5)$ $(x+3)(x-2)(6x-5)$ ?

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How do you multiply $(x + 3) (x - 2) (6 x - 5)$ $(x+3)(x-2)(6x-5)$ ?

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Answer 1 · 2016-10-27T04:20:20

$6 x^{3} + x^{2} - 41 x + 30$ $6x^3+x^2-41x+30$

Explanation:

Start by multiplying the first two then multiply the one you find by the third

$(x + 3) (x - 2) (6 x - 5) = (x^{2} + x - 6) (6 x - 5) = 6 x^{3} - 5 x^{2} + 6 x^{2} - 5 x - 36 x + 30 = 6 x^{3} + x^{2} - 41 x + 30$ $(x+3)(x-2)(6x-5)=(x^2+x-6)(6x-5)=6x^3-5x^2+6x^2-5x-36x+30=6x^3+x^2-41x+30$

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How do you multiply $(x + 3) (x - 2) (6 x - 5)$ $(x+3)(x-2)(6x-5)$ ?

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How do you multiply $(x + 3) (x - 2) (6 x - 5)$ $(x+3)(x-2)(6x-5)$ ?