Question

How do you multiply `(x+3)(x-2)(6x-5)`?

Answer 1

`6x^3+x^2-41x+30`

Explanation:

Start by multiplying the first two then multiply the one you find by the third

`(x+3)(x-2)(6x-5)=(x^2+x-6)(6x-5)=6x^3-5x^2+6x^2-5x-36x+30=6x^3+x^2-41x+30`

Hope this helps :)