color(white)(aa)3x+3y=9
color(red)(-4x+color(white)ay=3)
Multiiply the 2nd equation by -3. This will allow you to "cancel out" the y terms by adding the equations together. This technique is usually called "linear combination" or sometimes "elimination".
-3(color(red)(-4x+y=3))
color(red)(12x-3y=-9)
Rewrite with the first equation and add the two equations together.
color(white)(\a)3x+3y=color(white)(aa)9
color(red)(12x-3y=-9)
15x=0
(15x)/15=0/15color(white)(aaa)Divide both sides by 15
x=0
Substitute x=0 into either of the original equations. I will pick the first equation.
3x+3y=9
3(0)+3y=9
3y=9
(3y)/3=9/3color(white)(aaa)Divide both sides by 3
y=3
The solution is (0,3).