How do you simplify #(3x + 5) (2x - 3)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Nman · Shwetank Mauria Nov 30, 2016 #6x^2+x-15# Explanation: #(3x+5)(2x-3)# Starting with #3x#, multiply #3x# by each term in the second group #3x * 2x = 6x^2# #3x * -3 = -9x# Next, multiply #5#, by each term in the second group #5 * 2x = 10x# #5 * -3 = -15# Hence #(3x+5)(2x-3)# = #6x^2-9x+10x-15# = #6x^2+x-15# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 9948 views around the world You can reuse this answer Creative Commons License