How do you write $y+1/3=5/6(x+2/5)$ in slope intercept form?

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Answer 1 · 2017-01-20T22:11:00

$y=5/6x$

Slope-intercept form looks like:
$y=color(red)(m)x+color(red)(b)$

where $color(red)(m)$ is the value of the SLOPE
and $color(red)(b)$ is the value of the $y$ -INTERCEPT

Expand the left side of the equation:
$y+1/3=5/6x+10/30$
Reduce the fraction $10/30$
$y+1/3=5/6x+color(red)(1/3)$
Subtract $1/3$ from both sides of the equation:
$y+1/3 color(red)(-1/3)=5/6x+1/3 color(red)(-1/3)$
Simplify:
$y=5/6x+color(red)(0)$

$y=5/6x$

How do you write y+1/3=5/6(x+2/5)y+1/3=5/6(x+2/5) in slope intercept form?