How do you write $y + \frac{1}{3} = \frac{5}{6} (x + \frac{2}{5})$ $y+1/3=5/6(x+2/5)$ in slope intercept form?

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Answer 1 · 2017-01-20T22:11:00

$y = \frac{5}{6} x$ $y=5/6x$

Slope-intercept form looks like:
$y = m x + b$ $y=color(red)(m)x+color(red)(b)$

where $m$ $color(red)(m)$ is the value of the SLOPE
and $b$ $color(red)(b)$ is the value of the $y$ $y$ -INTERCEPT

Expand the left side of the equation:
$y + \frac{1}{3} = \frac{5}{6} x + \frac{10}{30}$ $y+1/3=5/6x+10/30$
Reduce the fraction $\frac{10}{30}$ $10/30$
$y + \frac{1}{3} = \frac{5}{6} x + \frac{1}{3}$ $y+1/3=5/6x+color(red)(1/3)$
Subtract $\frac{1}{3}$ $1/3$ from both sides of the equation:
$y + \frac{1}{3} - \frac{1}{3} = \frac{5}{6} x + \frac{1}{3} - \frac{1}{3}$ $y+1/3 color(red)(-1/3)=5/6x+1/3 color(red)(-1/3)$
Simplify:
$y = \frac{5}{6} x + 0$ $y=5/6x+color(red)(0)$

$y = \frac{5}{6} x$ $y=5/6x$

How do you write y+1/3=5/6(x+2/5)y+13=56(x+25)y+1/3=5/6(x+2/5) in slope intercept form?