Question

How do you simplify `sqrt2/sqrt6`?

Answer 1

Rationalize the denominator to get `sqrt3/3`

Explanation:

Start by multiplying the fraction by `sqrt6/sqrt6`,

`(sqrt6xxsqrt2)/(sqrt6xxsqrt6" "` Simplify to get

`sqrt12/6`

`=(sqrt4 xx sqrt3)/6" "` Finally, work out `sqrt4` in the numerator:

`=(2sqrt3)/6 = sqrt3/3`

Remember that `sqrtx/sqrty=sqrt(xy)/y`