How do you multiply $(7 n^{2} + 8 n + 7) (7 n^{2} + n - 5)$ $(7n^2+8n+7)(7n^2+n-5)$ ?

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How do you multiply $(7 n^{2} + 8 n + 7) (7 n^{2} + n - 5)$ $(7n^2+8n+7)(7n^2+n-5)$ ?

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Answer 1 · 2017-02-28T16:36:17

$49 n^{4} + 63 n^{3} + 22 n^{2} = 33 n - 35$ $49n^4 +63n^3 + 22n^2 = 33n - 35$

Explanation:

Distribution-
$(7 n^{2} + 8 n + 7) (7 n^{2} + n - 5)$ $(7n^2 + 8n + 7)(7n^2 + n - 5)$

Multiply $7 n^{2}$ $7n^2$ , $8 n$ $8n$ , and $7$ $7$ EACH by $7 n^{2}$ $7n^2$ , $n$ $n$ , and $- 5$ $-5$ .

For $7 n^{2}$ $7n^2$ :
$7 n^{2} \cdot 7 n^{2} = 49 n^{4}$ $7n^2*7n^2 = 49n^4$
$7 n^{2} \cdot n = 7 n^{3}$ $7n^2*n = 7n^3$
$7 n^{2} \cdot - 5 = - 35 n^{2}$ $7n^2*-5 = -35n^2$

do the same for $8 n$ $8n$ and $7$ $7$
You should get:
$(49 n^{4} + 7 n^{3} - 35 n^{2}) + (56 n^{3} + 8 n^{2} - 40 n) + (49 n^{2} + 7 n - 35)$ $(49n^4 + 7n^3 - 35n^2) + (56n^3 +8n^2 - 40n) +(49n^2 +7n - 35)$

Now combine like terms-

$49 n^{4} + 63 n^{3} + 22 n^{2} - 33 n - 35$ $49n^4 + 63n^3 + 22n^2 - 33n - 35$

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How do you multiply $(7 n^{2} + 8 n + 7) (7 n^{2} + n - 5)$ $(7n^2+8n+7)(7n^2+n-5)$ ?

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How do you multiply (7n^2+8n+7)(7n^2+n-5)(7n2+8n+7)(7n2+n−5)(7n^2+8n+7)(7n^2+n-5)?

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How do you multiply $(7 n^{2} + 8 n + 7) (7 n^{2} + n - 5)$ $(7n^2+8n+7)(7n^2+n-5)$ ?