Question

How do you multiply `(7n^2+8n+7)(7n^2+n-5)`?

Answer 1

`49n^4 +63n^3 + 22n^2 = 33n - 35`

Explanation:

Distribution-
`(7n^2 + 8n + 7)(7n^2 + n - 5)`

Multiply `7n^2`, `8n`, and `7` EACH by `7n^2`, `n`, and `-5`.

For `7n^2` :
`7n^2*7n^2 = 49n^4`
`7n^2*n = 7n^3`
`7n^2*-5 = -35n^2`

do the same for `8n` and `7`
You should get:
`(49n^4 + 7n^3 - 35n^2) + (56n^3 +8n^2 - 40n) +(49n^2 +7n - 35)`

Now combine like terms-

`49n^4 + 63n^3 + 22n^2 - 33n - 35`