Question

Assume that z scores are normally distributed with a mean of 0 and a standard deviation of 1. If `P(z<b)=.9817`, what is `b`?

Answer 1

`z=2.09`

Explanation:

`X~N(0,1)`

`P(z< b)=0.9817`

if we use Normal distribution tables we find that the values in them give us `P(X< b)` so we look for 0.9817 in the main body of the tables until we find the corresponding `z` value.

we see that `z=2.09`