How do you solve root3(x^2)= 9?
2 Answers
Undo each of the things done to
Explanation:
First, to undo the cube root, we can cube both sides to get
Next, to undo the square, we can take the square root of both sides to get
Explanation:
Given:
root(3)(x^2)=9
Note that
root(3)(x^2) = 3^2
Note that both
Cubing both sides of the equation, we get:
x^2 = (3^2)^3 = 3^(2*3) = 3^(3*2) = (3^3)^2 = 27^2
Subtract
x^2-27^2 = 0
The difference of squares identity can be written:
a^2-b^2 = (a-b)(a+b)
Using this with
0 = x^2-27^2 = (x-27)(x+27)
So:
x = +-27