How do you solve $4 x^{2} + 0.6 x = 0.54$ $4x^2+0.6x=0.54$ using the quadratic formula?

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How do you solve $4 x^{2} + 0.6 x = 0.54$ $4x^2+0.6x=0.54$ using the quadratic formula?

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Answer 1 · 2017-04-18T15:07:21

Get the equation into the correct form first. Then use the quadratic formula to solve.

$x = 0.3 or - 0.45$ $x=0.3 or -0.45$

Explanation:

$4 x^{2} + 0.6 x = 0.54$ $4x^2+0.6x=0.54$
$4 x^{2} + 0.6 x - 0.54 = 0$ $4x^2+0.6x-0.54=0$

Quadratic formula:
$x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$ $x=(-b+-sqrt(b^2-4ac))/(2a)$

Now plug in...
$x = \frac{- 0.6 \pm \sqrt{{0.6}^{2} - 4 \cdot 4 \cdot - 0.54}}{2 \cdot 4}$ $x=(-0.6+-sqrt(0.6^2-4*4*-0.54))/(2*4)$
$x = \frac{- 0.6 \pm \sqrt{0.36 + 8.64}}{8}$ $x=(-0.6+-sqrt(0.36+8.64))/(8)$
$x = \frac{- 0.6 \pm \sqrt{9}}{8}$ $x=(-0.6+-sqrt(9))/(8)$
$x = \frac{- 0.6 \pm 3}{8}$ $x=(-0.6+-3)/(8)$
$x = \frac{- 0.6 + 3}{8} = 0.3$ $x=(-0.6+3)/(8)=0.3$
$x = \frac{- 0.6 - 3}{8} = - 0.45$ $x=(-0.6-3)/(8)=-0.45$

FINAL ANSWER:

$x = 0.3 or - 0.45$ $x=0.3 or -0.45$

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How do you solve $4 x^{2} + 0.6 x = 0.54$ $4x^2+0.6x=0.54$ using the quadratic formula?

1 Answer

Explanation:

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How do you solve $4 x^{2} + 0.6 x = 0.54$ $4x^2+0.6x=0.54$ using the quadratic formula?