Question

How do you solve `4x^2+0.6x=0.54` using the quadratic formula?

Answer 1

Get the equation into the correct form first. Then use the quadratic formula to solve.

`x=0.3 or -0.45`

Explanation:

`4x^2+0.6x=0.54`
`4x^2+0.6x-0.54=0`

Quadratic formula:
`x=(-b+-sqrt(b^2-4ac))/(2a)`

Now plug in...
`x=(-0.6+-sqrt(0.6^2-4*4*-0.54))/(2*4)`
`x=(-0.6+-sqrt(0.36+8.64))/(8)`
`x=(-0.6+-sqrt(9))/(8)`
`x=(-0.6+-3)/(8)`
`x=(-0.6+3)/(8)=0.3`
`x=(-0.6-3)/(8)=-0.45`

FINAL ANSWER:

`x=0.3 or -0.45`